If it's not what You are looking for type in the equation solver your own equation and let us solve it.
5x^2+23x-9=0
a = 5; b = 23; c = -9;
Δ = b2-4ac
Δ = 232-4·5·(-9)
Δ = 709
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{709}}{2*5}=\frac{-23-\sqrt{709}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{709}}{2*5}=\frac{-23+\sqrt{709}}{10} $
| 5/16=t(t-5) | | 4-4x=6x-96 | | x^2-3.5=8.75 | | 8q^2-6q=7q^2-8q+48 | | 2(4x−1)=3(x+2) | | a+1/3-5/4=0 | | 4/7=x20 | | 12x-185=75-x | | 12m+8−5m+2+m=6(m+1) | | x+11=2x+1 | | -2(4-x)=6; | | 56(2x+1)=-138 | | 18x-224-9x=163 | | 27^x=x | | 5c+2=6 | | z/9+5=8 | | 7x+2x^2=-3 | | 4x=6+9 | | |4x-8|=16 | | b+10/14=6 | | 400x=300x | | t÷3-1=9 | | x^2-2x-18=-3 | | 3k^=-16k-5 | | 2x^-7x-5=0 | | 2^(5x-3)=15 | | 8(x-6)-6x-4=2 | | x3+-1x2+-48=0 | | Y’+2y=6 | | x+(x*2)+(x+2)=58 | | 9(x-1)=-3(x-9 | | 6+8y=62 |